Quadratic Equation Solver
Thinkforu.org Quadratic Equation Solver
Enter Equation Coefficients
For equation: ax² + bx + c = 0
Solution
Complete Guide to Solving Quadratic Equations
The Quadratic Formula
x = [-b ± √(b² - 4ac)] / (2a)
Example 1: Simple Quadratic Equation
Let's solve: x² + 5x + 6 = 0
Here, a = 1, b = 5, c = 6
Using the quadratic formula:
x = [-5 ± √(5² - 4(1)(6))] / (2(1))
x = [-5 ± √(25 - 24)] / 2
x = [-5 ± √1] / 2
x = [-5 ± 1] / 2
x = -2 or -3
Example 2: Complex Roots
Let's solve: x² + 2x + 5 = 0
Here, a = 1, b = 2, c = 5
Using the quadratic formula:
x = [-2 ± √(4 - 20)] / 2
x = [-2 ± √(-16)] / 2
x = -1 ± 2i
Pro Tips for Solving Quadratic Equations
Before using the quadratic formula, check if the equation can be factored easily.
The roots are where the parabola crosses the x-axis. The vertex tells you the minimum or maximum point.
b² - 4ac determines the type of roots:
• > 0: Two real roots
• = 0: One real root
• < 0: Two complex roots
Step-by-Step Guide
Write your equation in standard form (ax² + bx + c = 0) and identify a, b, and c.
Calculate b² - 4ac to determine the type of roots you'll get.
Use the quadratic formula: x = [-b ± √(b² - 4ac)] / (2a)
Reduce fractions and simplify radicals if possible.
Plug your solutions back into the original equation to check.
Frequently Asked Questions
• If positive: Two distinct real roots
• If zero: One repeated real root
• If negative: Two complex conjugate roots